{"id":218,"date":"2022-04-13T08:44:42","date_gmt":"2022-04-13T08:44:42","guid":{"rendered":"http:\/\/9thclass.deltapublications.in\/?page_id=218"},"modified":"2025-12-19T06:19:33","modified_gmt":"2025-12-19T06:19:33","slug":"m-1-construct-the-midpoint-or-perpendicular-bisector-of-a-segment","status":"publish","type":"page","link":"https:\/\/9thclass.deltapublications.in\/index.php\/m-1-construct-the-midpoint-or-perpendicular-bisector-of-a-segment\/","title":{"rendered":"M.1 Construct the midpoint or perpendicular bisector of a segment"},"content":{"rendered":"\n<h2 class=\"wp-block-heading has-text-align-center has-text-color has-huge-font-size\" style=\"color:#00056d;text-transform:uppercase\"><strong> Construct the midpoint or perpendicular bisector of a segment<\/strong><\/h2>\n\n\n\n<p class=\"has-text-color has-huge-font-size\" style=\"color:#74008b\">Key Notes :<\/p>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/i.ytimg.com\/vi\/IQ35R6CWqd8\/maxresdefault.jpg?utm_source=chatgpt.com\" alt=\"https:\/\/i.ytimg.com\/vi\/IQ35R6CWqd8\/maxresdefault.jpg?utm_source=chatgpt.com\" style=\"width:423px;height:auto\"\/><\/figure>\n\n\n\n<figure class=\"wp-block-image is-resized\"><img decoding=\"async\" src=\"https:\/\/i.ytimg.com\/vi\/jDswTWpBmWI\/sddefault.jpg?utm_source=chatgpt.com\" alt=\"https:\/\/i.ytimg.com\/vi\/jDswTWpBmWI\/sddefault.jpg?utm_source=chatgpt.com\" style=\"width:419px;height:auto\"\/><\/figure>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udd39 Basic Terms to Know<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Line segment<\/strong>: A part of a line with two endpoints.<\/li>\n\n\n\n<li><strong>Midpoint<\/strong>: The point that divides a line segment into <strong>two equal parts<\/strong>.<\/li>\n\n\n\n<li><strong>Perpendicular bisector<\/strong>: A line that<br>\u2714 cuts a segment into two equal parts<br>\u2714 meets the segment at <strong>90\u00b0 (right angle)<\/strong>.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udd39 Construction Tools<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li><strong>Compass<\/strong><\/li>\n\n\n\n<li><strong>Ruler (straightedge)<\/strong><br>\u274c Do <strong>not<\/strong> measure lengths with the ruler.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h2 class=\"wp-block-heading has-large-font-size\">\u270f\ufe0f Construction of the <strong>Midpoint<\/strong> of a Line Segment<\/h2>\n\n\n\n<p>Let the line segment be <strong>AB<\/strong>.<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>Place the compass at <strong>A<\/strong> and draw arcs <strong>above and below<\/strong> the segment.<\/li>\n\n\n\n<li>Without changing the compass width, place it at <strong>B<\/strong> and draw arcs cutting the previous arcs.<\/li>\n\n\n\n<li>Join the two intersection points of the arcs.<\/li>\n\n\n\n<li>The line drawn cuts <strong>AB<\/strong> at point <strong>M<\/strong>.<\/li>\n\n\n\n<li><strong>M is the midpoint<\/strong> of segment <strong>AB<\/strong>.<\/li>\n<\/ol>\n\n\n\n<p>\ud83d\udc49 This line is also the <strong>perpendicular bisector<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h2 class=\"wp-block-heading has-large-font-size\">\u270f\ufe0f Construction of the <strong>Perpendicular Bisector<\/strong><\/h2>\n\n\n\n<p>For the same segment <strong>AB<\/strong>:<\/p>\n\n\n\n<ol class=\"wp-block-list\">\n<li>With <strong>A<\/strong> as centre, draw arcs on both sides of the segment.<\/li>\n\n\n\n<li>With <strong>B<\/strong> as centre and the <strong>same radius<\/strong>, draw arcs intersecting the first pair.<\/li>\n\n\n\n<li>Join the intersection points.<\/li>\n\n\n\n<li>The line obtained:\n<ul class=\"wp-block-list\">\n<li>is <strong>perpendicular<\/strong> to AB<\/li>\n\n\n\n<li><strong>bisects<\/strong> AB into two equal parts.<\/li>\n<\/ul>\n<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udd39 Important Properties<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The perpendicular bisector always passes through the <strong>midpoint<\/strong>.<\/li>\n\n\n\n<li>Any point on the perpendicular bisector is <strong>equidistant from A and B<\/strong>.<\/li>\n\n\n\n<li>Construction is <strong>accurate<\/strong> and better than measurement.<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83e\udde0 Exam Tips<\/h3>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Always show <strong>construction arcs<\/strong> clearly.<\/li>\n\n\n\n<li>Label points neatly (A, B, M).<\/li>\n\n\n\n<li>Mention steps in <strong>logical order<\/strong>.<\/li>\n\n\n\n<li>Do not erase construction lines unless instructed.<\/li>\n<\/ul>\n\n\n\n<p class=\"has-text-align-center has-text-color has-large-font-size\" style=\"color:#105000\"><strong>Learn with an example<\/strong><\/p>\n\n\n\n<div class=\"wp-block-group has-background has-large-font-size\" style=\"background-color:#f3c9c9\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<div class=\"wp-block-group has-background-background-color has-background\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<p class=\"has-text-color\" style=\"color:#b00012\"><strong>Mark&nbsp;the midpoint of&nbsp;AB ?<\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"695\" height=\"521\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-2.png\" alt=\"\" class=\"wp-image-11953\" style=\"aspect-ratio:1.3339731285988483;width:508px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-2.png 695w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-2-300x225.png 300w\" sizes=\"auto, (max-width: 695px) 100vw, 695px\" \/><\/figure><\/div><\/div><\/div>\n\n\n\n<p>Part&nbsp;of the construction was done for you. Here are the steps to create this part of the&nbsp;construction.<\/p>\n\n\n\n<p><strong>Start&nbsp;with the objects in the diagram&nbsp;below.<\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"231\" height=\"236\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110556.974.png\" alt=\"\" class=\"wp-image-11954\" style=\"aspect-ratio:0.9788135593220338;width:247px;height:auto\"\/><\/figure><\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Draw a circle with radius AB centred at A.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"344\" height=\"312\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110654.503.png\" alt=\"\" class=\"wp-image-11955\" style=\"aspect-ratio:1.1025641025641026;width:298px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110654.503.png 344w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110654.503-300x272.png 300w\" sizes=\"auto, (max-width: 344px) 100vw, 344px\" \/><\/figure><\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Draw a circle with radius AB centred at B.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"360\" height=\"376\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110753.839.png\" alt=\"\" class=\"wp-image-11956\" style=\"aspect-ratio:0.9574468085106383;width:268px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110753.839.png 360w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110753.839-287x300.png 287w\" sizes=\"auto, (max-width: 360px) 100vw, 360px\" \/><\/figure><\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Mark the points where \u2a00A and \u2a00B intersect. Call them C and D.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"354\" height=\"407\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110847.016.png\" alt=\"\" class=\"wp-image-11957\" style=\"aspect-ratio:0.8697788697788698;width:262px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110847.016.png 354w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110847.016-261x300.png 261w\" sizes=\"auto, (max-width: 354px) 100vw, 354px\" \/><\/figure><\/div>\n\n\n<p>Since B and C are both on \u2a00A, AB=AC. Since A and C are both on \u2a00B, AB=BC. So, AB=AC=BC.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"341\" height=\"440\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110952.345.png\" alt=\"\" class=\"wp-image-11958\" style=\"aspect-ratio:0.775;width:217px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110952.345.png 341w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T110952.345-233x300.png 233w\" sizes=\"auto, (max-width: 341px) 100vw, 341px\" \/><\/figure><\/div>\n\n\n<p>Similarly, AB=AD=BD.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"399\" height=\"421\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111039.674.png\" alt=\"\" class=\"wp-image-11959\" style=\"aspect-ratio:0.9477434679334917;width:268px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111039.674.png 399w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111039.674-284x300.png 284w\" sizes=\"auto, (max-width: 399px) 100vw, 399px\" \/><\/figure><\/div>\n\n\n<p>So, C and D are equidistant from A and B.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Draw the line through C and D.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"358\" height=\"396\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111207.432.png\" alt=\"\" class=\"wp-image-11960\" style=\"aspect-ratio:0.9040404040404041;width:255px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111207.432.png 358w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111207.432-271x300.png 271w\" sizes=\"auto, (max-width: 358px) 100vw, 358px\" \/><\/figure><\/div>\n\n\n<p>Recall that the set of points equidistant from A and B form the perpendicular bisector of AB. Since C and D are equidistant from A and B, they lie on the perpendicular bisector. So , CD is the perpendicular bisector of AB.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"396\" height=\"438\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111334.500.png\" alt=\"\" class=\"wp-image-11961\" style=\"aspect-ratio:0.9041095890410958;width:266px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111334.500.png 396w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111334.500-271x300.png 271w\" sizes=\"auto, (max-width: 396px) 100vw, 396px\" \/><\/figure><\/div>\n\n\n<p><strong>Complete&nbsp;the&nbsp;construction.<\/strong><\/p>\n\n\n\n<p>To complete the construction of the midpoint o f AB , carry out the following step:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mark the point where CD and AB intersect. Call it E.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"339\" height=\"397\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111514.734.png\" alt=\"\" class=\"wp-image-11962\" style=\"aspect-ratio:0.853904282115869;width:264px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111514.734.png 339w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T111514.734-256x300.png 256w\" sizes=\"auto, (max-width: 339px) 100vw, 339px\" \/><\/figure><\/div>\n\n\n<p>Since CD is the perpendicular bisector of AB, the intersection E is the midpoint of AB.<\/p>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group has-background has-large-font-size\" style=\"background-color:#b2ecab\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<div class=\"wp-block-group has-background-background-color has-background\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<p class=\"has-text-color\" style=\"color:#b00012\"><strong>Mark&nbsp;the midpoint of&nbsp;AB?<\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"717\" height=\"528\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-3.png\" alt=\"\" class=\"wp-image-11963\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-3.png 717w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-3-300x221.png 300w\" sizes=\"auto, (max-width: 717px) 100vw, 717px\" \/><\/figure><\/div><\/div><\/div>\n\n\n\n<p>Part&nbsp;of the construction was done for you. Here are the steps to create this part of the&nbsp;construction.<\/p>\n\n\n\n<p><strong>Start&nbsp;with the objects in the diagram&nbsp;below.<\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"220\" height=\"194\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112407.824.png\" alt=\"\" class=\"wp-image-11964\"\/><\/figure><\/div>\n\n\n<ul class=\"wp-block-list\">\n<li><em>Draw&nbsp;a circle with radius&nbsp;AB&nbsp;centred at&nbsp;<\/em>A.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"315\" height=\"298\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112518.836.png\" alt=\"\" class=\"wp-image-11965\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112518.836.png 315w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112518.836-300x284.png 300w\" sizes=\"auto, (max-width: 315px) 100vw, 315px\" \/><\/figure><\/div>\n\n\n<ul class=\"wp-block-list\">\n<li><em>Draw&nbsp;a circle with radius&nbsp;AB&nbsp;centred at&nbsp;<\/em>B.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"391\" height=\"354\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112602.304.png\" alt=\"\" class=\"wp-image-11966\" style=\"aspect-ratio:1.1045197740112995;width:281px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112602.304.png 391w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112602.304-300x272.png 300w\" sizes=\"auto, (max-width: 391px) 100vw, 391px\" \/><\/figure><\/div>\n\n\n<ul class=\"wp-block-list\">\n<li>Mark the points where \u2a00A and \u2a00B intersect. Call them C and D.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"405\" height=\"380\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112659.950.png\" alt=\"\" class=\"wp-image-11967\" style=\"aspect-ratio:1.0657894736842106;width:273px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112659.950.png 405w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112659.950-300x281.png 300w\" sizes=\"auto, (max-width: 405px) 100vw, 405px\" \/><\/figure><\/div>\n\n\n<p>Since B and C are both on \u2a00A, AB=AC. Since A and C are both on \u2a00B, AB=BC. So, AB=AC=BC.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"456\" height=\"443\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112757.131.png\" alt=\"\" class=\"wp-image-11968\" style=\"aspect-ratio:1.0293453724604966;width:246px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112757.131.png 456w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112757.131-300x291.png 300w\" sizes=\"auto, (max-width: 456px) 100vw, 456px\" \/><\/figure><\/div>\n\n\n<p>Similarly, AB=AD=BD.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"508\" height=\"424\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112838.559.png\" alt=\"\" class=\"wp-image-11969\" style=\"aspect-ratio:1.1981132075471699;width:398px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112838.559.png 508w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112838.559-300x250.png 300w\" sizes=\"auto, (max-width: 508px) 100vw, 508px\" \/><\/figure><\/div>\n\n\n<p>So, C and D are equidistant from A and B.<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Draw the line through C and D.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"482\" height=\"453\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112958.021.png\" alt=\"\" class=\"wp-image-11970\" style=\"aspect-ratio:1.0640176600441502;width:312px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112958.021.png 482w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T112958.021-300x282.png 300w\" sizes=\"auto, (max-width: 482px) 100vw, 482px\" \/><\/figure><\/div>\n\n\n<p>Recall that the set of points equidistant from A and B form the perpendicular bisector of AB . Since C and D are equidistant from A and B, they lie on the perpendicular bisector. So , CD is the perpendicular bisector of AB.<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"551\" height=\"444\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T113125.641.png\" alt=\"\" class=\"wp-image-11971\" style=\"aspect-ratio:1.240990990990991;width:352px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T113125.641.png 551w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T113125.641-300x242.png 300w\" sizes=\"auto, (max-width: 551px) 100vw, 551px\" \/><\/figure><\/div>\n\n\n<p><strong>Complete&nbsp;the&nbsp;construction.<\/strong><\/p>\n\n\n\n<p>To complete the construction of the midpoint of AB , carry out the following step:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>Mark the point where CD and AB intersect. Call it E.<\/li>\n<\/ul>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img loading=\"lazy\" decoding=\"async\" width=\"551\" height=\"453\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T113307.241.png\" alt=\"\" class=\"wp-image-11972\" style=\"aspect-ratio:1.216335540838852;width:359px;height:auto\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T113307.241.png 551w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-05T113307.241-300x247.png 300w\" sizes=\"auto, (max-width: 551px) 100vw, 551px\" \/><\/figure><\/div>\n\n\n<p>Since CD is the perpendicular bisector of AB , the intersection E is the midpoint of AB.<\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-text-color has-large-font-size\" style=\"color:#d90000\">let&#8217;s practice!<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"500\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-81.png\" alt=\"\" class=\"wp-image-7931\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-81.png 500w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-81-300x300.png 300w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-81-150x150.png 150w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><\/figure>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<figure class=\"wp-block-image size-full\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"500\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-90.png\" alt=\"\" class=\"wp-image-7933\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-90.png 500w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-90-300x300.png 300w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-90-150x150.png 150w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><\/figure>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Construct the midpoint or perpendicular bisector of a segment Key Notes : \ud83d\udd39 Basic Terms to Know \ud83d\udd39 Construction Tools \u270f\ufe0f Construction of the Midpoint of a Line Segment Let the line segment be AB. \ud83d\udc49 This line is also the perpendicular bisector. \u270f\ufe0f Construction of the Perpendicular Bisector For the same segment AB: \ud83d\udd39<a class=\"more-link\" href=\"https:\/\/9thclass.deltapublications.in\/index.php\/m-1-construct-the-midpoint-or-perpendicular-bisector-of-a-segment\/\">Continue reading <span class=\"screen-reader-text\">&#8220;M.1 Construct the midpoint or perpendicular bisector of a segment&#8221;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-218","page","type-page","status-publish","hentry","entry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/218","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/comments?post=218"}],"version-history":[{"count":15,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/218\/revisions"}],"predecessor-version":[{"id":18319,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/218\/revisions\/18319"}],"wp:attachment":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/media?parent=218"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}