{"id":196,"date":"2022-04-13T08:41:18","date_gmt":"2022-04-13T08:41:18","guid":{"rendered":"http:\/\/9thclass.deltapublications.in\/?page_id=196"},"modified":"2025-12-04T12:07:14","modified_gmt":"2025-12-04T12:07:14","slug":"l-2-central-angles","status":"publish","type":"page","link":"https:\/\/9thclass.deltapublications.in\/index.php\/l-2-central-angles\/","title":{"rendered":"L.2 Central angles"},"content":{"rendered":"\n<h2 class=\"wp-block-heading has-text-align-center has-text-color has-link-color wp-elements-5f0a5cc3b6d19fc2431e1983e4e9fe5f\" id=\"block-eba7c9fe-ee2f-4181-b086-079710e6eccb\" style=\"color:#00056d;text-transform:uppercase\"><strong>Central angles<\/strong><\/h2>\n\n\n\n<p class=\"has-text-color has-link-color has-huge-font-size wp-elements-8550df6181cd5d83aa7a08ef336a4ca1\" style=\"color:#74008b\">Key Notes :<\/p>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udd35 <strong>What is a Central Angle?<\/strong><\/h3>\n\n\n\n<p>A <strong>central angle<\/strong> is an angle whose <strong>vertex is at the center<\/strong> of a circle.<br>Its <strong>rays<\/strong> (arms) point to the <strong>circumference<\/strong> of the circle.<br>\u27a1\ufe0f Example: Angle \u2220AOB in circle O.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udd34 <strong>Central Angle and Arc Measure<\/strong><\/h3>\n\n\n\n<p>A central angle <strong>cuts an arc<\/strong> on the circle.<br>\ud83d\udccf <strong>The measure of a central angle = the measure of its intercepted arc.<\/strong><br>\ud83d\udc49 If arc AB = 60\u00b0, then \u2220AOB = <strong>60\u00b0<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udfe3 <strong>Central Angle Formula (Radians)<\/strong><\/h3>\n\n\n\n<p>If the arc length = <em>s<\/em> and radius = <em>r<\/em><br>\ud83d\udc49 <strong>\u03b8 = s \/ r<\/strong> (in radians)<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udfe2 <strong>Full Circle Facts<\/strong><\/h3>\n\n\n\n<p>A circle has:<br>\ud83d\udd38 <strong>360\u00b0<\/strong> (degrees)<br>\ud83d\udd38 <strong>2\u03c0 radians<\/strong><br>\ud83d\udc49 Central angles add up to <strong>360\u00b0<\/strong>.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udfe1 <strong>Relationship With Inscribed Angles<\/strong><\/h3>\n\n\n\n<p>A central angle is <strong>twice<\/strong> the inscribed angle subtending the same arc.<br>\ud83d\udc49 \u2220Central = <strong>2 \u00d7 \u2220Inscribed<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udfe4 <strong>Sector Area and Central Angle<\/strong><\/h3>\n\n\n\n<p>A sector is the <strong>slice of a circle<\/strong> formed by a central angle.<br>If \u03b8 is in degrees:<br>\ud83d\udcd8 <strong>Sector Area = (\u03b8\/360) \u00d7 \u03c0r\u00b2<\/strong><\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<h3 class=\"wp-block-heading has-large-font-size\">\ud83d\udd35 <strong>Real-Life Uses of Central Angles<\/strong><\/h3>\n\n\n\n<p>\ud83c\udf17 Clock angles<br>\ud83d\udcca Pie charts<br>\ud83c\udfa1 Ferris wheel rotations<br>\u2699\ufe0f Engineering and construction<\/p>\n\n\n\n<p class=\"has-text-align-center has-text-color has-large-font-size\" style=\"color:#105000\"><strong>Learn with an example<\/strong><\/p>\n\n\n\n<div class=\"wp-block-group has-background has-large-font-size\" style=\"background-color:#ecbebe\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<div class=\"wp-block-group has-background-background-color has-background\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<p class=\"has-text-color has-link-color wp-elements-9f1b1484572e328d3b45a10bf49fe3ca\" style=\"color:#b00012\"><strong>What&nbsp;is&nbsp;\u2220GFI ?<\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" src=\"https:\/\/10thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/Add-a-subheading-3.png\" alt=\"\" class=\"wp-image-11677\" style=\"width:372px;height:auto\"\/><\/figure><\/div>\n\n\n<p>\u2220GFI = ______<strong>\u00b0<\/strong> <\/p>\n<\/div><\/div>\n\n\n\n<p>Look&nbsp;at the&nbsp;diagram:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" src=\"https:\/\/10thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-03T110808.504.png\" alt=\"\" class=\"wp-image-11678\" style=\"width:296px;height:auto\"\/><\/figure><\/div>\n\n\n<p>Write&nbsp;an equation showing that the measures of&nbsp;\u2220GFH,\u2220GFI&nbsp;and&nbsp;\u2220HFI&nbsp;sum to 360\u00b0, since they span an entire circle. Then solve for&nbsp;\u2220GFI.<\/p>\n\n\n\n<p>\u2220GFH + \u2220GFI + \u2220HFI = 360\u00b0<\/p>\n\n\n\n<p>150\u00b0 + \u2220GFI + 80<strong>\u00b0<\/strong> = 360\u00b0    Plug&nbsp;in<em>&nbsp;<\/em>\u2220GFH = 150\u00b0 <em>and&nbsp;<\/em> \u2220HFI =  80<strong>\u00b0<\/strong><\/p>\n\n\n\n<p>\u2220GFI  + 230\u00b0  = 360\u00b0   Combine&nbsp;like&nbsp;terms<\/p>\n\n\n\n<p>\u2220GFI  = 130\u00b0        Subtract&nbsp;230\u00b0  from both&nbsp;sides<\/p>\n\n\n\n<p>So, \u2220GFI  = 130\u00b0 <\/p>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group has-background has-large-font-size\" style=\"background-color:#c0e9b8\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<div class=\"wp-block-group has-background-background-color has-background\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<p class=\"has-text-color has-link-color wp-elements-2772eb768b0198bf988a81ae8bd9a20e\" style=\"color:#b00012\"><strong>What&nbsp;is&nbsp;\u2220RQS?<\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" src=\"https:\/\/10thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/Add-a-subheading-4.png\" alt=\"\" class=\"wp-image-11682\" style=\"width:338px;height:auto\"\/><\/figure><\/div>\n\n\n<p>&nbsp;\u2220RQS = _______<strong>\u00b0<\/strong> <\/p>\n<\/div><\/div>\n\n\n\n<p>Look&nbsp;at the&nbsp;diagram:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" src=\"https:\/\/10thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-03T112316.727.png\" alt=\"\" class=\"wp-image-11683\" style=\"width:362px;height:auto\"\/><\/figure><\/div>\n\n\n<p>Write&nbsp;an equation showing that the measures of&nbsp;\u2220RQS , \u2220RQT&nbsp;and&nbsp;\u2220SQT&nbsp;sum to 360\u00b0, since they span an entire circle. Then solve for&nbsp;\u2220RQS.<\/p>\n\n\n\n<p>\u2220RQS + \u2220RQT + \u2220SQT = 360\u00b0<\/p>\n\n\n\n<p>\u2220RQS+ 140\u00b0 + 120<strong>\u00b0<\/strong> = 360\u00b0    Plug&nbsp;in \u2220RQT = 140\u00b0 <em>and&nbsp;<\/em> \u2220SQT =  120<strong>\u00b0<\/strong><\/p>\n\n\n\n<p>\u2220RQS + 260\u00b0  = 360\u00b0   Combine&nbsp;like&nbsp;terms<\/p>\n\n\n\n<p>\u2220RQS = 100\u00b0        Subtract&nbsp;260\u00b0  from both&nbsp;sides<\/p>\n\n\n\n<p>So,  \u2220RQS = 100\u00b0 <\/p>\n<\/div><\/div>\n\n\n\n<div class=\"wp-block-group has-background has-large-font-size\" style=\"background-color:#d6def1\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<div class=\"wp-block-group has-background-background-color has-background\"><div class=\"wp-block-group__inner-container is-layout-constrained wp-block-group-is-layout-constrained\">\n<p class=\"has-text-color has-link-color wp-elements-2725214887f52b30265efb055fb2e6d4\" style=\"color:#b00012\"><strong>What&nbsp;is&nbsp;\u2220IHJ?<\/strong><\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" src=\"https:\/\/10thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/Add-a-subheading-7.png\" alt=\"\" class=\"wp-image-11702\" style=\"width:276px;height:auto\"\/><\/figure><\/div>\n\n\n<p>\u2220IHJ = _______\u00b0<\/p>\n<\/div><\/div>\n\n\n\n<p>Look&nbsp;at the&nbsp;diagram:<\/p>\n\n\n<div class=\"wp-block-image\">\n<figure class=\"aligncenter size-full is-resized\"><img decoding=\"async\" src=\"https:\/\/10thclass.deltapublications.in\/wp-content\/uploads\/2024\/01\/image-removebg-preview-2024-01-03T121716.834.png\" alt=\"\" class=\"wp-image-11704\" style=\"width:264px;height:auto\"\/><\/figure><\/div>\n\n\n<p>Write&nbsp;an equation showing that the measures of&nbsp;\u2220IHK , \u2220JHK&nbsp;and&nbsp;\u2220IHJ&nbsp;sum to 360\u00b0, since they span an entire circle. Then solve for&nbsp;\u2220IHJ.<\/p>\n\n\n\n<p>\u2220IHK + \u2220JHK + \u2220IHJ= 360\u00b0<\/p>\n\n\n\n<p> 140\u00b0 + 80<strong>\u00b0<\/strong> +\u2220IHJ = 360\u00b0    Plug&nbsp;in \u2220IHK = 140\u00b0 <em>and&nbsp;<\/em>  \u2220JHK&nbsp; =  80<strong>\u00b0<\/strong><\/p>\n\n\n\n<p>\u2220IHJ + 220\u00b0  = 360\u00b0   Combine&nbsp;like&nbsp;terms<\/p>\n\n\n\n<p>\u2220IHJ = 140\u00b0        Subtract&nbsp;220\u00b0  from both&nbsp;sides<\/p>\n\n\n\n<p>So,  \u2220IHJ= 140\u00b0 <\/p>\n<\/div><\/div>\n\n\n\n<p class=\"has-text-color has-large-font-size\" id=\"block-6c77eb4c-91a9-4942-9f09-4610c7b0cc70\" style=\"color:#d90000\">let&#8217;s practice!<\/p>\n\n\n\n<div class=\"wp-block-columns is-layout-flex wp-container-core-columns-is-layout-9d6595d7 wp-block-columns-is-layout-flex\">\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<figure class=\"wp-block-image size-full\"><a href=\"https:\/\/wordwall.net\/play\/88929\/780\/599\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"500\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-71.png\" alt=\"\" class=\"wp-image-7900\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-71.png 500w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-71-300x300.png 300w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-3-71-150x150.png 150w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><\/a><\/figure>\n<\/div>\n\n\n\n<div class=\"wp-block-column is-layout-flow wp-block-column-is-layout-flow\">\n<figure class=\"wp-block-image size-full\"><a href=\"https:\/\/wordwall.net\/play\/88928\/250\/438\"><img loading=\"lazy\" decoding=\"async\" width=\"500\" height=\"500\" src=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-80.png\" alt=\"\" class=\"wp-image-7902\" srcset=\"https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-80.png 500w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-80-300x300.png 300w, https:\/\/9thclass.deltapublications.in\/wp-content\/uploads\/2023\/05\/Worksheet-1-1-2-80-150x150.png 150w\" sizes=\"auto, (max-width: 500px) 100vw, 500px\" \/><\/a><\/figure>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Central angles Key Notes : \ud83d\udd35 What is a Central Angle? A central angle is an angle whose vertex is at the center of a circle.Its rays (arms) point to the circumference of the circle.\u27a1\ufe0f Example: Angle \u2220AOB in circle O. \ud83d\udd34 Central Angle and Arc Measure A central angle cuts an arc on the<a class=\"more-link\" href=\"https:\/\/9thclass.deltapublications.in\/index.php\/l-2-central-angles\/\">Continue reading <span class=\"screen-reader-text\">&#8220;L.2 Central angles&#8221;<\/span><\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"parent":0,"menu_order":0,"comment_status":"closed","ping_status":"closed","template":"","meta":{"om_disable_all_campaigns":false,"_monsterinsights_skip_tracking":false,"_monsterinsights_sitenote_active":false,"_monsterinsights_sitenote_note":"","_monsterinsights_sitenote_category":0,"footnotes":""},"class_list":["post-196","page","type-page","status-publish","hentry","entry"],"aioseo_notices":[],"_links":{"self":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/196","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages"}],"about":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/types\/page"}],"author":[{"embeddable":true,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/comments?post=196"}],"version-history":[{"count":16,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/196\/revisions"}],"predecessor-version":[{"id":18281,"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/pages\/196\/revisions\/18281"}],"wp:attachment":[{"href":"https:\/\/9thclass.deltapublications.in\/index.php\/wp-json\/wp\/v2\/media?parent=196"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}