Evaluate numerical expressions involving integers

key notes :

  • A numerical expression is a mathematical phrase that includes numbers and operations (such as addition, subtraction, multiplication, and division) but does not include an equals sign.

To correctly evaluate numerical expressions, follow the order of operations, often remembered by the acronym PEMDAS:

  • Parentheses
  • Exponents (not typically covered in 6th grade, but it’s good to be aware)
  • Multiplication and Division (from left to right)
  • Addition and Subtraction (from left to right)

Step 1: Parentheses

  • Solve expressions inside parentheses first.
  • Example: (3+4)×2

Step 2: Multiplication and Division

  • Perform all multiplication and division from left to right.
  • Example: 3+4×2

Step 3: Addition and Subtraction

  • Perform all addition and subtraction from left to right.
  • Example: 3+(4×2)

Simple Example:

  • 5+3×2
  • First, multiply: 3×2=6
  • Then, add: 5+6=11
  • (2+3)×4
  • First, solve inside parentheses: 2+3=5
  • Then, multiply: 5×4=20
  • 6−2×3+4÷2
  • First, multiply and divide from left to right:
  • 2×3=6
  • 4÷2=2
  • Then, add and subtract from left to right:
  • 6−6+2=0+2=2

Write Clearly:

  • Write each step of your work to avoid mistakes.

Double-Check:

  • Always double-check each operation to ensure accuracy.

Use Parentheses:

  • When in doubt, use parentheses to clarify the order of operations.

Practice:

  • Regular practice with different types of problems helps reinforce the rules.

Learn with an example

Evaluate the expression.

2+4÷2

First, identify the operations in the expression.

2+4÷2 This expression has addition and division.

The order of operations says to divide before adding.

2+4÷2=2+2

Now, add.2+2=4.

The value of the expression is 4.

Evaluate the expression for x = 5, y = 8 and z = 6.

(y2 + z) ÷ x

Solution :

= (y2 + x) ÷ x

Substitute x = 5, y = 8 and z = 6.

= (82 + 6) ÷ 5

= (64 + 6) ÷ 5

= 70 ÷ 5

= 14

Evaluate the expression for p = 6, q = 5 and r = 4.

(pq – 28)2 ÷ r

Solution :

(pq – 28)2 ÷ r

Substitute p = 6, q = 5 and r = 4.

= [(6)(5) – 28]2 ÷ 4

= (30 – 28)2 ÷ 4

= 22 ÷ 4

= 4 ÷ 4

= 1

Let’s Practice!